V_{dc}=V_{av}=\frac{2V_p}{\pi}
V_{ac}=V_p{\sqrt{ \frac{1}{2}-\frac{4} {\pi^2}}}
V_{RMS}=\sqrt {V_{dc}^2 + V_{ac}^2} = \frac {V_p} {\sqrt 2}
Thus, the total amount of energy is the same after and before the full wave rectifier.
luni, 29 martie 2010
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